Question

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Answer 1

g) √(6*2*3) + √(5*5*5) = √36 + √125 = 6 + 5√5

h) √(5*2) + √(5*5) - 5 - √10 = √10 + √25 - 5 - √10 = 0 + 5 - 5 = 0

i) √(8*2) - √(3*2) + √(6*1) - √(6*3) = √16 - √6 + √6 - √18 = 4 + 0 - 3√2 = 4 - 3√2

Answer 2

$g) \\ \\ \sqrt{6} \times \sqrt{2} \times \sqrt{3} + \sqrt{5} \times \sqrt{5} \times \sqrt{5} = \\ \\ \sqrt{36} + \sqrt{5} \times \sqrt{5} \times \sqrt{5} = \\ \\ 6 + \sqrt{5} \times \sqrt{5} \times \sqrt{5} = \\ \\ 6 + \sqrt{125} = \\ \\ 6 + 5 \sqrt{5}$

$h) \\ \\ \sqrt{5} \times ( \sqrt{2} + \sqrt{5}) - 5 - \sqrt{10} = \\ \\ \sqrt{10} + 5 - 5 - \sqrt{10} = \\ \\ \sqrt{10} - \sqrt{10} = \\ \\ 0$

$i) \\ \\ ( \sqrt{8} - \sqrt{3}) \times \sqrt{2} + \sqrt{6} \times (1 - \sqrt{3}) = \\ \\ (2 \sqrt{2} - \sqrt{3}) \times \sqrt{2} + \sqrt{6} \times (1 - \sqrt{3}) = \\ \\ \sqrt{2} \times (2 \sqrt{2} - \sqrt{3}) + \sqrt{6} \times (1 - \sqrt{3}) = \\ \\ 4 - \sqrt{6} + \sqrt{6} - 3 \sqrt{2} = \\ \\ 4 - 3 \sqrt{2}$