Question

Ajutor !! dau coroană​

Answer 1

Răspuns:

$\sqrt{6}$ × ( $\frac{4}{\sqrt{2} }$ - $\frac{3}{\sqrt{3} }$) + $\sqrt{18}$ - $\sqrt{48}$ =

$\frac{\sqrt{6}x(4\sqrt{3}-3\sqrt{2})}{\sqrt{6}}$ + $\sqrt{2x9}$ -  $\sqrt{3x16}$ =

4$\sqrt{3}$ - 3$\sqrt{2}$ + 3 $\sqrt{2}$- 4$\sqrt{3}$ = 0