Question

AJUTOR DAU CORONITA. numerele 247,297,347 impartite la x dau resturile 7 9 si 11. aflati x

Answer 1

247=x·c1+7
⇒x·c1=247-7
⇒x·c1=240;
297=x·c2+9
⇒x·c2=297-9
⇒x·c2=288;
347=x·c3+11
⇒x·c3=347-11
⇒x·c3=336;
⇒c.m.m.d.c=2⁴·3=16·3=48;
⇒x=48;