Question

Ajutor....Determinati numerele reale x si y stiind cax²+y²-2√3x+4√2y+11=0. 

Answer 1

$x^{2} -2 \sqrt{3} x+3+ y^{2} +2*2 \sqrt{2} y+8$
=$(x- \sqrt{3} )^{2} + (y+2 \sqrt{2}) ^{2} =0$
$x- \sqrt{3} =0 => x= \sqrt{3}$
$y+2 \sqrt{2}=0 => y=-2 \sqrt{2}$