Question

Ajutor ex 2 in special a sa fie corect

Answer 1

Răspuns:

fractie supraunitara=numarator > numitor

17/(2x-1)

2x-1 < 17=>2x < 17+1=>x < 18:2=> x < 9

x=0,1,2...8

___________

y/27=8/12

12y=27·8=>y=216:12=>y=18

__________

(z+2)/(2z-1)=2/3

3(z+3)=2(2z-1)

3z+9=4z-2

9+2=4z-3z=>z=11

Answer 2

Explicație pas cu pas:

a)17/2x-1 supraunitara =》2x-1<17

2x<18=》x<9

x={0,1,2,3,4,5,6,7,8}

b)y/27=8/12=》y×12=27×8

y×12=216 =》y=18

c)z+2/2z-1=2/3

3(z+2)=2(2z-1)

3z+6=4z-2

z=8