Question

AJUTOR IMI TREBUIE PANA LA FIX​

Answer 1

Salut,

Știm formula generală:

$(x^n)\ ^{'}=n\cdot x^{n-1}.$

$f(x)=x^2+\dfrac{1}{x^2}=x^2+x^{-2}.\\\\f\ ^{'}(x)=2\cdot x^{2-1}+(-2)\cdot x^{-2-1}=2x-2\cdot x^{-3}=2x-\dfrac{2}{x^3}.\\\\Deci\ f\ ^{'}(x)=2x-\dfrac{2}{x^3}.$

Ai înțeles ?

Green eyes.