Question

Ajutor la problema 10? Va rog rezolvari complete :D

Answer 1

10a)
2 1/3×√0,09+3 1/2×√0,04-1/6×√0,36=
=7/3×0,3+7/2×0,2-1/6×0,6=
=0,7+0,7-0,1=1,3

b) 1 1/4×√0,0225-0,(3)×√0,81+0,2(7)×√0,0324=
0,(3)=3/9=1/3
0,2(7)=(27-2)/90=25/90=5/18
= 5/4×0,15-1/3×0,9+5/18×0,18=
= 0,1875-0,3+0,5=0,3875

c) 2,(3)×√0,(1)+√324/25:√81/225-√1024:√64=
2,(3)=(23-2)/9=21/9=7/3
√0,(1)=√1/9=1/3
=7/3×1/3+18/5:9/15-32/8=
=7/9+18/5×15/9-4=
=7/9+6-4=
=7/9+2=
=25/9=2,(7)