Question

Ajutor,maine am matematica! dau coroana! exercitiile 1,2,3 si 5

Answer 1

2a) =(√3+1)/(3-1)=(√3+1)/2

=(√7+√5)/(7-5)=(√7+√5)/2

=√5/10

b) =-√3/5√3=simplificam cu √3=-1/5

=(3√2·√3)/2·3=3√6/6=√6/2

=(-5√3·√5)/3·5=simplif cu 5=-√15/3

3a) =(x+2)/(x-2)(x+2)=simplif cu x+2=1/(x-2)

b) =x(3-x)/(3-x)(3+x)= simplif cu 3-x=x/(3+x)

c) =(2x-1)(2x+1)/3(2x-1)= simplif cu 2x-1=(2x+1)/3

5a) =(3x-1)(3x-1)/(3x-1)(3x+1)= se simplif cu 3x-1=(3x11)/(3x+1)

b) =[(x²+10x+25)-(x²-10x+25)]/x=
=(x²+10x+25-x²+10x-25)/x=20x/x=20