Question

Ajutor (nu e ft greu...); )

Answer 1

$a = \Big[4^{60}\cdot (3^4)^{20}\cdot 5^{30}+19\Big]:\Big[(2^{20})^6\cdot (9^8)^5\cdot 25^{15}+437:23\Big]+15^7:15^5\\ \\ a = (2^{120}\cdot 3^{80}\cdot 5^{30}+19):(2^{120}+3^{80}\cdot 5^{30}+19) + 15^2 \\ \\ a = 1+15^2\\ \\ \boxed{a = 226} \\ \\ \\ b = 455+4\cdot \Big[(2^2\cdot 5^2-3^4\cdot 12:36+2^4\cdot 3):11^2\Big]\\ \\ b = 455+4\cdot \Big[(10^2-3^3\cdot 36:36+2^4\cdot 3):11^2\Big] \\ \\ b = 455+4\cdot\Big[(100 - 27+48):121\Big] \\ \\ b = 455+4\cdot (121:121) \\ \\ b = 455+4 \\ \\ \boxed{b = 459}$

Între 225 și 459 sunt cuprinse (459 - 226) - 1 = 234 numere naturale.

Answer 2

a=[(2²)⁶⁰*3⁸⁰*5³⁰+19]/[2¹²⁰*(3²)⁴⁰*(5²)¹⁵+19]+15²

a=(2¹²⁰*3⁸⁰*5³⁰+19)/(2¹²⁰*3⁸⁰*5³⁰+19)+225

a=1+225

a=226

437:23=19

23

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207

207

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b=455+4*[(10²-3⁴*12/36+16*3)/121]

b=455+4*[100-81*1/3+48)/121]

b=455+4*[(100-27+48)/121]

b=455+4*121/121

b=455+4*1

b=455+4

b=459

a=226 si b=459

n=numarul de termeni

n=459-226+1=234 (de termeni)