Question

Ajutor!!! Ofer 30 de puncte !!

Answer 1

$a)2 - \frac{x}{2} = \frac{3 + x}{2} + 4 \: | \times 2$

$4 - x = 3 + x + 8$

$- x - x = 3 + 8 - 4$

$- 2x = 7 \: | \times ( - 1)$

$2x = - 7$

$x = - \frac{7}{2} \: \in \: \mathbb{R}$

$b)4x - \frac{x + 1}{6} = \frac{2x}{6} - \frac{1}{6} \: | \times 6$

$24x - x - 1 = 2x - 1$

$24x - x - 2x = - 1 + 1$

$21x = 0$

$x = 0 \: \in \: \mathbb{R}$

$c) \frac{16x + 2}{9} - \frac{x + 1}{3} = - x + 1 \: | \times 9$

$16x + 2 - 3(x + 1) = - 9x + 9$

$16x + 2 - 3x - 3 = - 9x + 9$

$16x - 3x + 9x = 9 - 2 + 3$

$22x = 10 \: | \div 2$

$11x = 5$

$x = \frac{5}{11} \: \in \: \mathbb{R}$

$d)1 + \frac{2x - 1}{3} - 2 \frac{1}{9} = 2.0(5)$

$1+\frac{2x-1}{3}-\frac{2\times9+1}{9}=\frac{205-20}{90}$

$1+\frac{2x-1}{3}-\frac{19}{9}=\frac{185}{90}$

$1+\frac{2x-1}{3}-\frac{19}{9}=\frac{37}{18}\:|\times18$

$18+6(2x-1)-2\times19=37$

$18+12x-6-38=37$

$12x=37-18+6+38$

$12x=63$

$x=\frac{63}{12}\:\in\:\mathbb{R}$

$e)\frac{x+1}{2}+\frac{x+2}{3}+\frac{x+3}{4}=0\:|\times12$

$6(x+1)+4(x+2)+3(x+3)=0$

$6x+6+4x+8+3x+9=0$

$6x+4x+3x=-6-8-9$

$13x=-23$

$x=-\frac{23}{13}\:\in\:\mathbb{R}$

$f)1.1(6)x-2\frac{1}{2}(x+2)=5x-9$

$\frac{116-11}{90}-\frac{2\times2+1}{2}(x+2)=5x-9$

$\frac{105}{90}-\frac{5}{2}(x+2)=5x-9$

$\frac{7}{6}-\frac{5x+10}{2}=5x-9 \:|\times30$

$5\times7-15(5x+10)=150x-270$

$35-75x-150=150x-270$

$-75x-150x=-270-35+150$

$-225x=-155\:|\times(-1)$

$225x=155$

$x=\frac{155}{225}$

$x=\frac{31}{45}\:\in\:\mathbb{R}$

$g)1.5-\frac{x-1}{4}=\frac{x}{2}+\frac{5(1-2x)}{4}$

$1.5-\frac{x-1}{4}=\frac{x}{2}+\frac{5-10x}{4}\:|\times4$

$6-x+1=2x+5-10x$

$-x-2x+10x=5-6-1$

$7x=-2$

$x=-\frac{2}{7}\:\in\:\mathbb{R}$