Question

ajutor :P
(x+1)[3(x+2)-2(x-1)]-4(x+2)
(x-2)[(x+5)-3(x+6)]-x(x-4)

Answer 1

(x+1)[3(x+2)-2(x-1)]-4(x+2)= (x-1)(3x+6-2x+2) - 4x+8=(x-1)(x+8)-4x+8=
=x² +7x-8-4x+8=x²+3x

(x-2)[(x+5)-3(x+6)]-x(x-4) =(x-2)(x+5-3x-18) -x²+4x=(x-2)(-2x-13) -x²+4x=

= - (x-2)(2x+13) -x²+4x = - (2x²+13x-4x-26) -x²+4x= -2x²-9x+26 -x²+4x=

= -3x²-5x+26