Question

Ajutor Pls
0,6(3)+0,25 supra lui 0,75-0,(3) = 0,6(3) supra lui a =?
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Answer 1

0,6(3)=(63-6)/90=57/90

0,25=25/100=1/4

0,75=75/100=3/4

0,(3)=3/9=1/3

57/90+1/4×4/3-1/3=57/90×1/a

57/90+1/3-1/3=57/90×1/a

1/a×57/90=57/90

1/a=57/90:57/90

1/a=1

a=1

Answer 2

$\it 0,6(3)+\dfrac{^{100)}0,25}{\ \ 0,75}-0,(3)=\dfrac{0,6(3)}{a} \Rightarrow \dfrac{63-6}{90}+\dfrac{\ \ 25^{(25}}{75}-\dfrac{\ \ 3^{(3}}{9}=\dfrac{\dfrac{63-6}{90}}{a} \Rightarrow\\ \\ \\ \Rightarrow \dfrac{57}{90}+\dfrac{1}{3}-\dfrac{1}{3}=\dfrac{57}{90a} \Rightarrow \dfrac{57}{90}=\dfrac{57}{90a}\Big |_{\cdot\dfrac{90}{57}} \Rightarrow 1=\dfrac{1}{a} \Rightarrow a=1$