Question

Ajutor pls dau coroana​

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

Răspuns:

$- \frac{3 \sqrt{3} }{4}$

Explicație pas cu pas:

Salutare ! ᕕ( ᐛ )ᕗ

$\frac{4 - \sqrt{24} }{ \sqrt{32} } + \frac{6 \sqrt{6} + 9}{4 \sqrt{27} } - \frac{6 + 4 \sqrt{6} }{6 \sqrt{12} } - \frac{8 + \sqrt{24} }{3 \sqrt{8} }$

$\frac{4 - 2 \sqrt{6} }{4 \sqrt{2} } + \frac{3(2 \sqrt{6} + 3) }{12 \sqrt{3} } - \frac{2(3 + 2 \sqrt{6} )}{12 \sqrt{3} } - \frac{8 + 2 \sqrt{6} }{6 \sqrt{2} }$

$\frac{2(2 - \sqrt{6} )}{4 \sqrt{2} } + \frac{2 \sqrt{6} + 3 }{4 \sqrt{3} } - \frac{3 + 2 \sqrt{6} }{6 \sqrt{3} } - \frac{2(4 + \sqrt{6} ) }{6 \sqrt{2} }$

$\frac{2 - \sqrt{6} }{2 \sqrt{2} } + \frac{(2 \sqrt{6} + 3) \sqrt{3} }{12} - \frac{(3 + 2 \sqrt{6} ) \sqrt{3} }{18} - \frac{4 + \sqrt{6} }{3 \sqrt{2} }$

$\frac{(2 - \sqrt{6} ) \sqrt{2} }{4} + \frac{2 \sqrt{18} + 3 \sqrt{3} }{12} - \frac{3 \sqrt{3} + 2 \sqrt{18} }{18} - \frac{(4 + \sqrt{6} ) \sqrt{2} }{6}$

$\frac{2 \sqrt{2} - \sqrt{12} }{4} + \frac{6 \sqrt{2} + 3 \sqrt{3} }{12} - \frac{3 \sqrt{3} + 6 \sqrt{2} }{18} - \frac{4 \sqrt{2} + \sqrt{12} }{6}$

$\frac{2 \sqrt{2} - 2 \sqrt{3} }{4} + \frac{3(2 \sqrt{2} + \sqrt{3}) }{12} - \frac{3( \sqrt{3} + 2 \sqrt{2} )}{18} - \frac{4 \sqrt{2} + 2 \sqrt{3} }{6}$

$\frac{2( \sqrt{2} - \sqrt{3} ) }{4} + \frac{2 \sqrt{2} + \sqrt{3} }{4} - \frac{ \sqrt{3} + 2 \sqrt{2} }{6} - \frac{2(2 \sqrt{2} + \sqrt{3} )}{6}$

$\frac{ \sqrt{2} - \sqrt{3} }{2} + \frac{2 \sqrt{2} + \sqrt{3} }{4} - \frac{ \sqrt{3} + 2 \sqrt{2} }{6} - \frac{2 \sqrt{2} + \sqrt{3} }{3}$

$\frac{ \sqrt{2} - \sqrt{3} }{2} - \frac{2 \sqrt{2} + \sqrt{3} }{12} - \frac{ \sqrt{3} + 2 \sqrt{2} }{6}$

$\frac{6( \sqrt{2} - \sqrt{3}) - (2 \sqrt{2} + \sqrt{3} ) - 2( \sqrt{3} + 2 \sqrt{2}) }{12}$

$\frac{6 \sqrt{2} - 6 \sqrt{3} - 2 \sqrt{2} - \sqrt{3} - 2 \sqrt{3} - 4 \sqrt{2} }{12}$

$\frac{ - 9 \sqrt{3} }{12}$

$\frac{ - 3 \sqrt{3} }{4}$

$- \frac{3 \sqrt{3} }{4}$

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