Question

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Answer 1

Răspuns:

5.

$\sqrt{4 + 2 \sqrt{3} } - \sqrt{ \sqrt{9} } + 3 - 2 \sqrt{3 } = \\ \sqrt{(1 + 3) {}^{2} } - \sqrt{3} + 3 - 2 \sqrt{3} = \\ 1 + \sqrt{3} - \sqrt{3} + 3 - 2 \sqrt{3} = \\ 1 + 3 - 2 \sqrt{3} = \\ 4 - 2 \sqrt{3}$