Question

AJUTOR! PROBLEMA 94:

Answer 1

notam:  a suma Iuliei

              b suma lui Danut

a+4000=b-4000 => a+8000=b  (1)

b+4000=3·(a-4000)

b+4000=3·a-12000

b=3·a-12000-4000

b=3·a-16000   (2)

Din (2)=(1) => 3·a-16000=a+8000

3·a-a=16000+8000

2·a=24000

a=24000:2

a=12000 lei;  

(1)=> b=a+8000

b=12000+8000

b=20000 lei

R: Iulia are 12000 lei;  Danut are 20000 lei