Question

ajutor repede !!!!!!!! dau coroana √2+4√3-5√2+7√3-1=
4√3 x 5√7
21√8:7√2
8√54-6√92+√24
√5x(4-2√5+7√2)-(8-7√10)
Rationalizati numitori
a) 5/9√5
b) 14/√7

Answer 1

1) √2 + 4√3 - 5√2 + 7√3 - 1 = 11√3 - 4√2 - 1

2) 4√3 × 5√7 = 20√21

3) 21√8 ÷ 7√2 = 42√2 ÷ 7√2 = 6

4)8√54 - 6√92 + √24 = 24√6 - 12√23 + 2√6 = 26√6 - 12√23

5) √5 × (4 - 2√5 + 7√2) - (8 - 7√10) = 4√5 - 10 + 7√10 - 8 + 7√10 = 14√10 + 4√5 - 18

a) 5 / 9√5 = 5√5 / 9√5² = 5√5 / 45 = √5 / 9

b) 14 / √7 = 14√7 / 7 = 2√7

Answer 2

Răspuns:

Explicație pas cu pas:

√2 + 4√3 - 5√2 + 7√3 - 1 =

= ( √2 - 5√2 ) + ( 4√3 + 7√3 ) - 1 =

= - 4√2 + 11√3 - 1 =

= 11√3 - 4√2 - 1

___________________

4√3 × 5√7 = 20√21

________________

21√8 : 7√2 = 3×2√2 / √2 = 6√2/√2 = 6

_______________________________

8√54 - 6√92 + √24 =

= 8 × 3√6 - 6 × 2√23 + 2√6 =

= 24√6 - 12√23 + 2√6 =

= 26√6 - 12√23

____________________

√5 × ( 4 - 2√5 + 7√2 ) - ( 8 - 7√10 ) =

= 4√5 - 2 × 5 + 7√10 - 8 + 7√10 =

= 4√5 - 10 - 8 + 14√10 =

= 14√10 + 4√5 - 18

___________________________

a)   5/9√5 = 5√5/(9×5) = √5/9

b)   14/√7 = 14√7/7 = 2√7