Question

ajutor repede
x=(3^2+1)*2
y=(3^2-1)*2
sa se afle media geometrica si media aritmetica rezolvare completa
radicalul-(^)
la patrat-(*)

Answer 1

Răspuns:

Explicație pas cu pas:

x=$(3\sqrt{2} +1)^{2} = (3\sqrt{2} )^{2} +2*3\sqrt{2} +1=18+6\sqrt{2} +1=19+6\sqrt{2}$

$y= (3\sqrt{2} -1)^{2} = (3\sqrt{2})^{2}-2*3\sqrt{2}  +1= 18-6\sqrt{2} +1=19-6\sqrt{2}$

ma= $\frac{x+y}{2}= \frac{19+6\sqrt{2} +19-6\sqrt{2} }{2}=\frac{38}{2}=19$

mg=$\sqrt{x*y}=\sqrt{(19+6\sqrt{2})*(19-6\sqrt{2})  }  =\sqrt{19^{2}-(6\sqrt{2}) ^{2}  } =\sqrt{361-72} =\sqrt{289}=17$

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