Question

Ajutor!!!
Sa se rezolve ecuatia: [(9/4)^(3x+1)]*radical din [(8/27)^(6x)]=3/2

Answer 1

(9/4)^3x+1 • radical din (8/27)^6x = 3/2

(3/2)^6x+2 • (8/27)^3x = (3/2)^1

(3/2)^6x+2 • (2/3)^9x = (3/2)^1

(3/2)^6x+2 • (3/2)^-9x = (3/2)^1

(3/2)^-3x+2 = (3/2)^1

-3x + 2 = 1

-3x = 1 - 2

-3x = -1

x = 1/3