Question

AJUTOR!
Se amesteca in raport de masa 1:2 o solutie de HCl 60%cu o alta solutie de HCl 20%. Calculati procentatia solutiei finale.​

Answer 1

notam ms1 = a si ms2 = b

ms1 : ms2 = a : b = 1 : 2

=> 2a = b

ms.finala = ms1 + ms2 = a + b = a + 2a = 3a g

stim ca c% = mdx100/ms

=> c1 = md1x100/ms1 = 100md1/a

=> md1 = ac1/100 = 60a/100 = 0,6a        

=> md2 = bc2/100 = 20b/100 = 0,2b = 0,4a

=> md.final = md1 + md2 = 0,6a + 0,4a = a

=> c.f. = md.finalx100/ms.final

= 100a/3a = 33,33%