Question

ajutor urgenta va rog
dau coroana
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Answer 1

Răspuns:

Explicație pas cu pas:

4a) f'(x) = -16x +1

b) f'(x) = (x-3)'(x+1) - (x-3)(x+1)'/(x+1)^2 =

(x+1 -x +3)/(x+1)^2 = 4/(x+1)^2

5a) f'(x) = 4(x^3 +x)^3*(x^3+ x)' = 4(x^3 +x)^3*(3x^2 +1)

b) f'(x) = (3x+1)'/(2√(2x +1)) = 3/(2√(2x +1))

6c)   i^2 = -1,     -i^2 = 1

(2+i)(3-4i)/((3+4i)(3-4i))=

(6 -8i +3i -4i^2)/(9-16i^2)=

(10 -5i)/(9+16) = 5(2-i)/25 = (2 -i)/5