Question

Ajutor!!! Va eog sa ma ajutati, am nevoie pana luni dimineata, chiar si o problema ma ajuta.

Answer 1

12)Diagonala=12√2→latura =12 cm
Perimetrul=4xlatura=4x12=48 cm

Answer 2

7.) a.)l=4cm => h=l√3/2=4√3/2=2√3._____ ______________________________ b.)l=6√3cm=> h=l√3/2=6√3•3/2=6•3/2=3•3=9__ ___________________________ c.)l=x => h=l√3/2=x√3/2______ ___________________________ 11.)l=6cm si L=8cm.Desenam diagonala care uneste cele 2 laturi.obs ca se creeaza un triunghi dreptunghic,iar diagonala(d) este ipotenuza => d²=l²+L² => d²=6²+8² => d²=36+64 => d²=100 => d=√100=10cm ____________________________ 6.)a.)l=8 => d=l√2=8√2._______ ____________________________b.)l=15√2 =>d=l√2=15√2•√2=15•2=30._____ ____________________________c.)l=x => d=l√2=x√2________ ________________________________5.)obs ca folosind teorema lui pitagora si efectuand niste calc obt o formula mai simpla: Ip-ipotenuza.=> ip²=c²+c² => ip²=2c² => ip=√2c² => ip=c√2. C-cateta si nu este alta decat latura.=> a.)l=12 => ip=l√2=12√2____________________________________________________b.)l=9√2 => ip=l√2=9√2•√2=9•2=18____________________________________________c.)l=x => ip=l√2=x√2