Question

ajutor va rog!!!!!!!!!!

Answer 1

Δ ADB dreptunghic ∡D=90  ,∡B=60 , ∡C=30
BD cateta care se opune unghiului de 30 si este jumatate din ipotenuza
BD=AB/2=8/2=4
AD²=AB²-BD²=8²-4²=64-16=48
AD=√48=4√3

ΔADC dreptunghic isoscel
AD=4√3
AD=DC=4√3
AC²=(4√3)²+(4√3)²=48+48=96

AC=√96=4√6

BC=BD+DC=4+4√3=4(1+√3)
P=AB+BD+AC=8+4(1+√3)+4√6=4(2+1+√3+√6)=4(3+√3+√6)

PR=BC/2=4(1+√3)/2=2(1+√3)
RQ=AB/2=8/2=4
PD=AC/2=4√6/2=2√6
BQ=BC/2=4(1+√3)/2=2(1+√3)
BQ=BD+DQ
2(1+√3)=4+DQ
DQ=2(√3-2)

P=PD+DQ+QR+PR=2√6+2(√3-2)+4+2(1+√3)=2√6+2√3-4+4+2+2√3=2√6+4√3+2=2(√6+2√3+1)