Question

Ajutor vă rog........

Answer 1

Bună!

$\frac{28}{31} *[4^{-1} +(2\frac{1}{2}-\frac{7}{4} )*\frac{7}{8} ]=$

$=\frac{28}{31} *[\frac{1}{4}+(\frac{2*2+1}{2} -\frac{7}{4} )*\frac{8}{7} ]=$

$=\frac{28}{31} *[\frac{1}{4} +(^{2)} \frac{5}{2}-\frac{7}{4}) *\frac{8}{7} ]=$

$= \frac{28}{31} *(\frac{1}{4} +\frac{3}{4} *\frac{8}{7} )=$

$=\frac{28}{31} *(^{7)} \frac{1}{4}+^{4)} \frac{6}{7} )=$

$=\frac{28}{31} *\frac{31}{28}=$

$=1$ ✅