Question

AJUTOR VA ROG AJUTATI MA AM NEVOIE URGENT!!! DAU COROANA !!!!​

Answer 1

Răspuns:

$a) \: (5 \sqrt{2} + \frac{4}{ \sqrt{6} } ) \times \sqrt{3 } - (4 \sqrt{3} + \frac{12}{ \sqrt{6} } ) \times \sqrt{2} + 2( \sqrt{12} - \sqrt{2} ) = \\ = (5 \sqrt{2} + \frac{2 \sqrt{6} }{3} ) \times \sqrt{3} - (4 \sqrt{3} + 2 \sqrt{6} ) \times \sqrt{2} + 2(2 \sqrt{3} - \sqrt{2} = \\ = 5 \sqrt{6} + \frac{2 \sqrt{18} }{3} - (4 \sqrt{6} + 2 \sqrt{12} ) + 4 \sqrt{3} - 2 \sqrt{2} = \\ = 5 \sqrt{6} + \frac{6 \sqrt{2} }{3} - (4 \sqrt{6 } + 4 \sqrt{3} ) + 4 \sqrt{3} - 2 \sqrt{2} = \\ = 5 \sqrt{6} - 4 \sqrt{6} - 4 \sqrt{3} + 4 \sqrt{3} = \\ = 5 \sqrt{6 } - 4 \sqrt{6} = \\ = \sqrt{6}$

$b) \: 8 - \sqrt{3} ( \sqrt{6} + 2 \sqrt{5} ) - ( \frac{10 \sqrt{3} }{ \sqrt{5} } - \frac{12 \sqrt{5} }{ \sqrt{3} } ) + \sqrt{2} (1 - 4 \sqrt{2} ) = \\ = 8 - \sqrt{18} - 2 \sqrt{15} - (2 \sqrt{15} - 4 \sqrt{15} ) + \sqrt{2} - 8 = \\ = 8 - \sqrt{18} - 2 \sqrt{15 } + 2 \sqrt{15} + \sqrt{2} - 8 = \\ = - \sqrt{18} + \sqrt{2} = \\ = - 3 \sqrt{2} + \sqrt{2} = \\ - 2\sqrt{2}$