Question

Ajutor va rog (atasament).

Answer 1

   
[tex]\displaystyle\\ \overline{z} \text{ este conjugatul lui }z. \\ \\ 3z + 2\overline{z} = 3+2i \\ \\ 3(a+bi)+2(a-bi)=3+2i\\\\ 3a+3bi + 2a - 2bi = 3+2i\\\\ 3a + 2a +3bi -2bi = 3+2i\\\\ 5a + bi = 3+2i\\\\ 5a = 3 ~~~\Longrightarrow~~~\boxed{a = \frac{3}{5}} \\\\ bi = 2i ~~~\Longrightarrow~~~\boxed{b = 2}\\\\ \text{Solutia este: } ~~~~~ \boxed{\boxed{z = \frac{3}{5} + 2i}}[/tex]