Question

AJUTOR! VA ROG! Daca x este masura unui unghi ascuit si sin x= 3 supra 5, calculati cos x si tg x

Answer 1

sin^2 x+cos^2 x=1
cos^2 x= 1 - sin^2 x
cos^2 x = 1 - 9/25
cos^2 x =(25-9)/25=16/25 => cos x=4/5
tg x = sin x / cos x = 3/5 * 5/4 = 3/4

Answer 2

se aplica formula:sin²x+cos²x=1;sin²x=(3/5)²=9/25
9/25+cos²x=1
cos²x=1-9/25
cos²x=25/25-9/25
cos²x=16/25⇒cosx=√16/25=4/5→cosx=4/5
tgx=sinx/cosx=(3/5)/(4/5)=3/5×5/4=3/4→tgx=3/4