Question

ajutor,va rog!
Dau coroana!​

Answer 1

Răspuns:

a=1/3-{1/3-[1/3-3/2·(⁴⁾1/3-³⁾1/4)]}

a=1/3-{1/3-[1/3-3/2·(4/12-3/12)]}

a=1/3-[1/3-(1/3-3/2·1/12)]

a=1/3-[1/3-(⁸⁾1/3-³⁾1/8)]

a=1/3-[1/3-(8/24-3/24)]

a=1/3-(⁸⁾1/3-5/24)

a=⁸⁾1/3-3/24

a=8/24-3/24

a=5/24

b=[0,(3)+(1/3)²]·1,5

b=(3/9+1/9)·(15/10)⁽⁵

b=4/9·3/2

b=(12/18)⁽⁶

b=2/3

c=0,8(3):2,(3)·(1+1/2·1/3)

c=[(83-8)/90:(23-2)/9]·(⁶⁾1+1/6)

c=(75/90:21/9)·(6/6+1/6)

c=75/90·9/21·7/6

c=5/12

a=5/24

b=⁸⁾2/3=16/24

c=²⁾5/12=10/24

5/24 , 5/12 , 2/3

ca sa ordonam crescator aducem fractiile la acelasi numitor comun