Question

Ajutor va rog frumos

Answer 1

A) se reduce 3 cu 9 si 4 cu 8 si atunci avem
5/2x1/7x1/3=(5x1x1)/(2x7x3)=5/42

B) se imparte 18 la 9 si ramane
1/1x2/5x2/7=(1x2x2)/(1x5x7)=4/35

C)se imparte 10 la 2 si 14 la 7
1/1x3/5x2/10=(1x3x2)/(1x5x10)=6/50:2=3/25

D) (2x2+1)/2x3/5x1/2=5/2x3/5x1/2=3/2x1/2=3/4
Se imparte 5 cu 5