Question

Ajutor , va rog . Mersi , salut .

Answer 1

Răspuns:

Explicație pas cu pas:

$a)\begin{pmatrix}2&3\\ 1&4\end{pmatrix}+\begin{pmatrix}1&-2\\ 3&1\end{pmatrix}=\begin{pmatrix}3&1\\ 4&5\end{pmatrix}\\\\b) 2\begin{pmatrix}2&3\\ 1&4\end{pmatrix}+3\begin{pmatrix}1&-2\\ 3&1\end{pmatrix} = \begin{pmatrix}4&6\\ 2&8\end{pmatrix} + \begin{pmatrix}3&-6\\ 9&3\end{pmatrix} = \begin{pmatrix}7&0\\ 11&11\end{pmatrix}\\\\c) \begin{pmatrix}2&3\\ \:\:\:1&4\end{pmatrix}\cdot \begin{pmatrix}1&-2\\ \:\:\:3&1\end{pmatrix} =$

$=\begin{pmatrix}2\cdot \:1+3\cdot \:3&2\left(-2\right)+3\cdot \:1\\ 1\cdot \:1+4\cdot \:3&1\cdot \left(-2\right)+4\cdot \:1\end{pmatrix} = \begin{pmatrix}11&-1\\ 13&2\end{pmatrix}$