Question

Ajutor va rog muuulttt de tot​

Answer 1

Răspuns:

a) Aria unui triunghi dreptunghic este semiprodusul catetelor.

T. bisect.

BA/AD = BC/CD

BA/12 = BC/36 => BA = BC/3

T. Pitagora

BA^2 + 48^2 = 9BA^2

8BA^2 = 48^2

BA^2 = 6×48 = 288 => BA = 12rad2 cm

Aria = (12rad2 × 48)/2 = 288rad2 cm^2

b) ED || BC =>tr. AED ~ tr. ABC =>AE/AB=AD/AC=ED/BC

AE/12rad2 = 12/48 = 1/4

=>AE = 3rad2 cm = BF

ED/36rad2 = 1/4 => ED = BF = 9rad2

Perimetrul = 2×3rad2 + 2×9rad2 = 24rad2 cm