Matematică, întrebare adresată de nustiucenumesapun222, 8 ani în urmă

Ajutor va rog, si cat mai repede posibil daca se poate!!

Anexe:

Răspunsuri la întrebare

Răspuns de iakabcristina2
1

a)(x-a)(x+a)

(x-5)(x+5)

(x-3)(x+3)

(1-2x)(1+2x)

(x-1)(x+1)

b)(x-1)(x+1)

(x-2)(x+2)

(2-x)(2+x)

(x-3)(x+3)

(3-x)(3+x)

c)(x-5)(x+5)

(x-9)(x+9)

(x-7)(x+7)

(7-x)(7+x)

d)(x-8)(x+8)

(1-x)(1+x)

(3y-2)(3y+2)

(2-y)(2+y)

(7x-5)(7x+5)

e)(4y-3)(4y+3)

(7-y)(7+y)

(xy-rad3)(xy+rad3)

(yx-rad2)(yx+rad2)

(rad5-ax)(rad5+ax)

(2x-rad7)(2x+rad7)

(rad13-x)(rad13+x)

f)(5x/4 -2)(5x/4 +2)

(2/3 -x)(2/3 +x)

(3x -5/4)(3x +5/4)

(9/4 -x)(9/4 +x)

g)(x -1/2)(x +1/2)

(x/10 -1)(x/10 +1)

(2/5 -x)(2/5 +x)

h)((x-brad3)(x+brad3)

(rad3 - xrad6)(rad3 + xrad6)

(rad6-x)(rad6+x)

(xrad5-rad3)(xrad5+rad3)

(x-rad11)(x+rad11)

i)(rad3-3x)(rad3+3x)

(x^2 - xrad7)(x^2 + xrad7)

(x-4)(x+4)

(15-x)(15+x)

j)(2a/5 -2x)(2a/5 +2x)

(1/2 -y)(1/2 +y)

(5y/2 -3a)(5y/2 +3a)

k)(11a/10 -x/5)(11a/10 +x/5)

(3a/10 -y/10)(3a/10 +y/10)

l)(a+b-3)(a+b+3)

(x+4-x-1)(x+4+x+1)=3(2x+5)

m)(x-3-9-x)(x-3+9+x)=-12(2x+6)=-24(x+3)

(2x+1+x-3)(2x+1-x+3)=(3x-2)(x+4)

n)(5x-4-x+3)(5x-4+x-3)=(4x-1)(6x-7)

(3x+1-x-2)(3x+1+x+2)=(2x-1)(4x+3)

o)(4-x-5x-1)(4-x+5x+1)=(3-6x)(4x+5)=-3(2x-1)(4x+5)

(2x-1-3x+1)(2x-1+3x-1)=-x(5x-2)

p)(x/10 - 1 - x/10 + 3)(x/10 - 1 + x/10 - 3) = 2(x/5 - 4) = (2x/5 - 2)


nustiucenumesapun222: MULTUMESC DIN TOT SUFLETUL!!!
iakabcristina2: Cu drag :)
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