Question

ajutor va rogg am nev

Answer 1

a)   ( - 1 / 5 )⁶ x ( - 1 / 5 )⁴ = ( - 1 / 5 )  ⁽ ⁶ ⁺ ⁴ ⁾ = ( - 1 / 5 ) ¹⁰  Adevarat

      ==> avand aceeasi baza, adun exponentii

b)  ( - 1 / 9 )²  : ( - 1 / 3 ) ² =

Obs.   ( - 1 / 9 ) ² = ( - 1² / 3² )² = ( - 1 / 3 )⁴

= ( - 1 / 3 ) ⁴ : ( - 1 / 3 )² =

= ( - 1 / 3 ) ⁽ ⁴ ⁻ ² ⁾ =

= ( - 1 / 3 )² ==> Adevarat

= ( - 1 / 9 )² : 1² / 3² =

=  ( 1 / 9 )² : ( 1 / 9 ) =  ==> ( - )² = +

= ( 1 / 9 ) ⁽ ² ⁻ ¹ ⁾ = 1 / 9 = ( 1 / 3 )²

c)   [ - 11,(6)]⁶ x [ - 11,(6)]⁰ = [ - 11,(6) ] ⁽ ⁶ ⁺ ⁰ ⁾ = [ - 11,(6) ]⁶ ==> Adevarat

d)   ( - 0,2 )¹³ : ( - 0,2) ⁵ = -  0,2⁸  ==> Fals

= ( - 0,2 ) ⁽ ¹³ ⁻ ⁵ ⁾ =

= ( - 0,2) ⁸ =

= 0.2⁸; deoarece ( -) la putere pozitiva e plus ( + )