Question

Ajutor va rogggggggggg​

Answer 1

Am adăugat o poză. Succes!

Answer 2

$\bold{k)} \ 2^{6n} \mid (8^{2n+1}+4^{3n+1}-11\cdot 64^n) =\\ =(2^3)^{2n+1}+(2^2)^{3n+1}-11\cdot (2^6)^n=\\=2^{6n+3}+2^{6n+2}-11\cdot 2^{6n}=\\=2^{6n}(2^3+2^2-11)= \\ =2^{6n}(8+4-11)=\boxed{2^{6n}};$