Question

Ajutorr
Repede va rog!

Answer 1

a)
$(( \sqrt{5} + 3) + ( \sqrt{5} - 3)) \div 2 = \\ ( \sqrt{5 } + 3 + \sqrt{5} - 3) \div 2 = \\ 2 \sqrt{5} \div 2 = \sqrt{5}$
b)
$((2 \sqrt{3} + 1) + (3 \sqrt{3} - 1) + \sqrt{3} ) \div 3 = \\ (2 \sqrt{3} + 1 + 3 \sqrt{3} - 1 + \sqrt{3} ) \div 3 = \\ 6 \sqrt{3} \div 3 = 2 \sqrt{3}$
c)
$(4 \sqrt{5} + 2 \sqrt{5} + 5 \sqrt{5} + 9 \sqrt{5} ) \div 4 = \\ 20 \sqrt{5} \div 4 =5 \sqrt{5}$
d)
$( \frac{2}{ \sqrt{3} } + \frac{4}{ \sqrt{12} } ) \div 2 = \\ ( \frac{2}{ \sqrt{3} } + \frac{4}{2 \sqrt{3} } ) \times \frac{1}{2 } = \\ ( \frac{2}{ \sqrt{3} } + \frac{2}{ \sqrt{3} } ) \times \frac{1}{2} = \\ \frac{4}{ \sqrt{3} } \times \frac{1}{2} = \frac{2}{ \sqrt{3} }$

e)
$((2 \sqrt{3} + \sqrt{7} ) + (2 \sqrt{7} + \sqrt{3} )) \div 2 = \\ (2 \sqrt{3} + \sqrt{7} + 2 \sqrt{7} + \sqrt{3} ) \div 2 = \\( 3 \sqrt{3} + 3 \sqrt{7} ) \div 2 = \\ \frac{3 \sqrt{3} + 3 \sqrt{7} }{2 }$