Question

Ajutorrr!determina valoarea lui a din fiecare egalitate 27÷[26+(6×a-7×3)÷9]+(13-2×2×3)=2.repede va roggg

Answer 1

Răspuns:

27:[26+(6a-7·3)÷9]+(13-2·2·3)=2

27:[26+(6a-7·3)÷9]+(13-12)=2

27:[26+(6a-21):9]+1=2

27:[26+(6a-21):9]=2-1

26+(6a-21):9=27:1

(6a-21):9=27-26

6a-21=1·9

6a=9+21

a=30:6

a=5

Answer 2

27÷[26+(6×a-7×3)÷9]+(13-2×2×3)=2

27÷[26+(6×a-21)÷9]+(13-4×3)=2

27÷[26+(6×a-21)÷9]+(13-12)=2

27÷[26+(6×a-21)÷9]+1=2

27÷[26+(6×a-21)÷9]=2-1

27÷[26+(6×a-21)÷9]=1

26+(6×a-21)÷9=27÷1

26+(6×a-21)÷9=27

(6×a-21)÷9=27-26

(6×a-21)÷9=1

6×a-21=1×9

6×a-21=9

6×a=9+21

6×a=30

a=30÷6

a=5

verificare

_________

27÷[26+(6×5-7×3)÷9]+(13-2×2×3)=2

27÷[26+(30-21)÷9]+(13-4×3)=2

27÷(26+9÷9)+(13-12)=2

27÷(26+1)+1=2

27÷27+1=2

1+1=2