Question

ajutorrr urgent vă roggg​

Answer 1

Explicație pas cu pas:

${(x - 2)}^{3} = {x}^{3} - 3 \cdot {x}^{2} \cdot 2 + 3 \cdot x \cdot {2}^{2} - {2}^{3} = {x}^{3} - 6 \cdot {x}^{2} + 12 \cdot x \cdot - 8$

$\dfrac{16}{49} - {a}^{2} = {\Big(\dfrac{4}{7} \Big)}^{2} - {a}^{2} = \Big(\dfrac{4}{7} - a \Big)\Big(\dfrac{4}{7} + a \Big)$

$(0,2 - 3x)(0,2 + 3x) = {(0,2)}^{2} - {(3x)}^{2} = 0,04 - 9 {x}^{2}$

${(2 + 3x)}^{2} = {2}^{2} + 2 \cdot 2 \cdot 3x + {(3x)}^{2} = 4 + 12x + 9{x}^{2}$

${a}^{3} + {(2b)}^{3} = (a + 2b)( {a}^{2} - a \cdot 2b + {b}^{2} = (a + 2b)( {a}^{2} - 2ab + {b}^{2})$