Question

Ajutorrrr!!! Calculati media geometrica a numerelor a=3+2√2 si b=3-2√2

Answer 1

[tex] \sqrt{(3+2 \sqrt{2})*(3-2 \sqrt{2})} \\ \\ \text{Observatie! Avem deaface cu o diferenta de patrate.} \\ \\ = \sqrt{3^2-(2 \sqrt{2})^2 } \\ = \sqrt{9-4*2} \\ = \sqrt{9-8} \\ = \sqrt{1} =1 [/tex]

Mult noroc!