Question

Ajutorrrrr
Va rogggggggggg

Answer 1

| 3 /x³-8|=| 1 /x-2| <=> existenta celor 2 numere are loc daca si numai daca x∈R\{2} .

Daca x >2 => | 1 /x-2|=1 pentru x=3 si |1 /x-2|=0 pentru x >3 .

| 1 /x-2|=1 <=> | 3 /x³-8|=1 dar deoarece x=3 => 3 /x³-8=3 /19 => 0 < 3/19 <1 <=> | 3/19|=0=1 ,contradictie asadar x≠3 .

| 1 /x-2|=0 <=> | 3 /x³-8|=0 <=> 0 <= 3 /x³-8 <1 <=> x∈R\{2;3} .

Daca x <2 => | 1 /x-2|=-1 <=> | 3 /x³-8|=-1 <=> -1 <= 3 /x³-8 <0  => x∈(-∞,2) .

Asadar x∈R\{2;3} ∪ (-∞,2) <=> x∈R\{2;3} .