Question

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Answer 1

1) AT=BT ( T mij MN,AM=NB) => BT=11 cm=1,1 dm.

2) <C= 180⁰-(<A+<B)=180⁰-110⁰=70⁰.

arcul AB=2×<C=2×70⁰=140⁰.

3) <AOM=180⁰-<BOM=180⁰-120⁰=60⁰.

ON bisectoarea <AOM => <MON=<AON=<AOM/2=60⁰/2=30⁰.

=> <BON=<BOM+<MON=120⁰+30⁰=150⁰.

4) AC= înălțime.

BC=BD-CD=25-9=16 cm.

=> teorema înălțimii => AC²=BC×CD =>

AC²=16×9 => AC²=144 => AC=12 cm=d(A,DB).