Question

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Answer 1

a) Aabc= BC x AD/2= 28x24/2= 336 cm^2

b) d(B, AC)= hAC (inaltimea dusa din B pe AC)

Aabc= hAC x AC/2

hAC= 2Abc/AC= 2x336/30= 22,4 cm^2

c) In orice triunghi, avem formula A= pr

p- semiperimetrul= perimetrul/2

r- raza cercului inscris triunghiului

r= A/p

p= 26+28+30/2= 42 cm

r= 336/42= 8 cm