Question

AJUTORRRRRRRRRRRRRRRRRRRRRRRRRRRRRR!!!!!!! În câte zerouri se termina (a+b) la puterea 2 ​

Answer 1

a=10⁵⁹-9•10⁵⁸=10⁵⁸•(10-9)

a=10⁵⁸

b=5⁴•25¹¹•125¹⁰•2⁵⁶+2⁵⁷+2⁵⁸+2⁵⁹

b=5⁴•(5²)¹¹•(5³)¹⁰•2⁵⁶(1+2¹+2²+2³)

b=5⁴•5²²•5³⁰•2⁵⁶•15

b=5⁵⁶•2⁵⁶•15

b=10⁵⁶•15

(a+b)²=(10⁵⁸+10⁵⁶•15)²

(a+b)²=[10⁵⁶•(10²+15)]²

(a+b)²=10¹¹²•115²

=>112 zerouri