Question

AJUTROR!!!
Ajutatima la E, am termen limita pana maine ora 12

Answer 1

E.

a. se cere natura at. de C

1= cuaternar , 2 = tertiar , 3= primar

b.

Fm. = C8H16, miu = 8x12+16x1 = 112 g/mol

raport de masa:

C: H = 96: 16 /:16 = 6: 1

c.

daca la 112g C8H16 ..................... 96g C

           x g C8H16 ........................ 72g C

           = 84g C8H16

d.

Fm. omolog inferior = C7H14

Fm. omolog superior = C9H18

e.

       CH3

CH3-C-CH2-C=CH2

       CH3     CH3

2,5,5-trimetil-1-pentena

f.

CH2=CH-CH2-CH2-CH2-CH2-CH2-CH3

1-octena