Question

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Answer 1

4. b)  $( \frac{1}{3}+ \frac{1}{3}*7)*(35.6:356)=( \frac{1}{3}+ \frac{7}{3})*0.1= \frac{8}{3}* \frac{1}{10}= \frac{4}{3}* \frac{1}{5}= \frac{4*1}{3*5}= \frac{4}{15}$

f) [0.4*3.3-1]:0.5+0.1=[1.32-1]:0.5+0.1=0.32:0.5+0.1=0.64+0.1=0.74

h) [1.6+0.25]:1.916=$1.85: \frac{479}{250} = \frac{32}{20}* \frac{250}{479}= \frac{37}{2}* \frac{25}{479}= \frac{37*25}{2*479}= \frac{925}{958}$