Question

alati a b c daca sunt d.p cu 3,7 si 8 si 2a +5b- 4c=108

Answer 1

a/3=b/7 =c/8 =k
a/3=k   ;        a =3k
b/7 =k   ;        b =7k
c/8 =k ;           c =8k

2a+5b-4c =108
2*3k+5*7k-4*8k =108
6k+35k-32k =108
9k =108
k =12
a=3k ;      a =3*12 =36
b =7k  ;     b =7*12 =84
c=8k  ;       c =8*12 =96
v  ;   2*36+5*84-4*96 =72+420-384 =108