Question

alculati media aritmetica ponderata anumerelor rationale poziti e a) 1,25 si 1,1(6) cu ponderele 2 si respecti 3

Answer 1

=(1,25*2+1,1(6)*3)/(2+3)

=(125/100*2+1*((16-1)/90)*3)/5

=(2,5+0,5)/5

=3/5