Question

alfa numărul necunoscut.a) 32:e=(36:6+42:7)-4×2 b)23-20:2+4×8+7×7-74+g=4×6 c)(2×2+2-2:2×2)×(2×2-2:1)×h=8×8:8×10 d)63:7+27:3-(48+8):(11-3)=i+9 ​

Answer 1

Sper ca te-am ajutat

Answer 2

Răspuns: a)8, b)4, c)10 d)2

Explicație pas cu pas:

a) 32:e=(6+6)-8   32:e=12-8  32:e=4  e=32:4  e=8

b) 23-10+32+49-74+g=24  13+32+49-74+g=24  45+49-74-g=24  94-74+g=24  20+g=24  g=24-20  g=4

c) (4+2-2)x(4-2) x h=80  (6-2)x2xh=80  4x2xh=80  8xh=80  h=80:8  h=10

d) 9+9-56:8=i+9  18-7=i+9  11=i+9  i=11-9  i=2

(sper ca te a ajutat)

:)