Question

alfati nr antural x: {10^3+10^2*[10+(5^2-x):5]}:20^2=6
*= ori
^=la puterea
VA ROOG DAU COROANA!!!

Answer 1

Explicație pas cu pas:

X:{1000+100x[10+(25-x):5]}:400=6

X:[1000+100x(10+25-x:5)]:400=6

X:[1000+100x(10+5-x)]:400=6

X:(1000+100x (15-x):400=6

X:(1000+1500-100x):400=6

X:(2500-100x):400=6

X:2400x:400=6

X:2400x=400x6

X:2400=2400

X=2400:2400

X=1

Sper sa fie bine