Question

Alfati nr ratural X din egalitatea 1+2×{3+4×[5+6:(7-X)]}=63

Answer 1

2×{3+4×[5+6:(7-X)]}=63 - 1 = 62
Impartim la 2:
3+4×[5+6:(7-X)] = 62:2 = 31
4×[5+6:(7-X)] = 31 - 3 = 28

Impartim la 4:
5+6:(7-X) =  28:4 = 7
6:(7-X) = 7 - 5 = 2
6 = 2 × (7 - x)
Impartim la 2:
3 = 7 - x
x = 7 - 3
x = 4