Question

Am A (-1;6), B (9,8), C (3,6)
Aflati distanta de la A la mijlocul lui BC

Answer 1

Fie M mijlocul lui BC.
$x_{M} = \frac{ x_{B+ x_{C} } }{2}= \frac{9+3}{2} =6$
$y_{M} = \frac{ y_{B} + y_{C} }{2} = \frac{8+6}{2} = 7$
⇒ M ( 6,7 )
d(A,M) = $\sqrt{ ( y_{M} - y_{A} )^{2} + ( x_{M} - x_{A} )^{2} } = \sqrt{ (7-6)^{2}+ (6+1)^{2} } = \sqrt{50} =5 \sqrt{2}$