Question

Am de facut,doar ca imi trebuie si rezolvarea:Ofer 40 puncte!!!
a)-0,(5)x+0,(2)=0,(6)
b)3x+7=x-2
c)2(x-1)+4=5(x+2)+3
d)1/2x-1/3=1/6x+2

Answer 1

$\displaystyle a).-0,(5)x+0,(2)=0,(6) \\ - \frac{5}{9} x+ \frac{2}{9} = \frac{2}{3} \\ -5x+2=3 \cdot 2 \\ -5x+2=6 \\ -5x=6-2 \\ -5x=4 \\ x=- \frac{4}{5}$

$\displaystyle b).3x+7=x-2 \\ 3x-x=-2-7 \\ 2x=-9 \\ x=- \frac{9}{2}$

$\displaystyle c).2(x-1)+4=5(x+2)+3 \\ 2x-2+4=5x+10+3 \\ 2x-5x=10+3+2-4 \\ -3x=11 \\ x=- \frac{11}{3}$

$\displaystyle d). \frac{1}{2} x- \frac{1}{3} = \frac{1}{6} x+2 \\ 3x-2=x+2 \cdot 6 \\ 3x-2=x+12 \\ 3x-x=12+2 \\ 2x=14 \\ x= \frac{14}{2} \\ x=7$